10m^2=11m+23

Solution for 10m^2=11m+23 equation:

10m^2=11m+23

We move all terms to the left:

10m^2-(11m+23)=0

We get rid of parentheses

10m^2-11m-23=0

a = 10; b = -11; c = -23;
Δ = b2-4ac
Δ = -112-4·10·(-23)
Δ = 1041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1041}}{2*10}=\frac{11-\sqrt{1041}}{20}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1041}}{2*10}=\frac{11+\sqrt{1041}}{20}
$